Connect the multimeter between base and emitter.
Note the voltage reading and explain what this reading is indicating.
According to my experiment which I did with voltmeter across base and emitter my reading was 0.802v which is a good reading therefore it means that my transistor is saturated and working well.
Connect the multimeter Between collector and emitter. Note the voltage reading and explain what this reading is indicating.
In this experiment I connected my voltmeter across the collector and the emitter therefore my reading was 53.2mV.
In the plot given below what are the regions indicated by the arrows A & B?
Hows does a transistor work in these regions? Explain in details:
In the region marked A the transistor is fully sturated and works fine whereas the region B is the cut off therefore the transistor is not been sturated and it is not working due to lack of current and voltage.
What is the power dissipated by the transistor at Vce of 3 volts?
Pd = Vce x Ic
= 3v x 12.5mV
= 37.5v
What is the Beta of this transistor at Vce 2,3 & 4volts ?
B= Ib/Ic
Vce 2v = 20/0.8 = 25 is the Beta
Vce 3v = 12.5/0.5 = 25 is the Beta
Vce 4v = 5/0.2 = 25 is the Beta
This indicates and tells me that the Beta is same at all stages of the graph.
Just because you have 0.82 V at Vbe does not mean that the transistor is "saturated and working well" (don't say "working well"; it is either working or not working i.e. 'on' or 'off').
ReplyDeleteYou have not explained what Vce at 53.2 mV means.
How can a transistor "work fine"?
The Pd is not 37.5 V.
What is Beta?